Charges +q and –q are placed at points A and B respectively which are a distance 2 L apart, C is the midpoint between A and B. The work done in moving a charge +Q along the semicircle CRD is:

Text Solution
Verified by ExpertsThe correct answer is:
D
Work done is equal to change in potential energy.
In Ist case, when charge + Q is situated at C.
Electric potential energy of system in that case

U 1 =
+
+
. 
In IInd case, when charge +Q is moved from C to D.
Electric potential energy of system in that case

U 2 =
+
.
+

Work done =
U = U 2 – U 1
= 
=
.
=
c
=
= – 
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